Calculate the tensile stress anpplied at maximum load

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SUMMARY

The discussion focuses on calculating tensile stress in a steel cable used in a hoist system. The cable has a diameter of 25mm, a maximum permissible working stress of 200N/mm², and a maximum load of 75kN. The cross-sectional area was correctly calculated as approximately 490.87 mm² using the formula πR². To find the tensile stress, participants are guided to apply the formula σ = F/A, which will determine if the stress remains within permissible limits.

PREREQUISITES
  • Understanding of tensile stress and its significance in materials science
  • Familiarity with the formula σ = F/A for calculating stress
  • Knowledge of Young’s modulus of elasticity and its application
  • Basic skills in geometry for calculating the area of a circle
NEXT STEPS
  • Calculate tensile stress using the formula σ = F/A with F as 75kN and A as 490.87 mm²
  • Determine if the calculated tensile stress exceeds the maximum permissible working stress of 200N/mm²
  • Calculate strain using the formula ε = σ/E, where E is Young’s modulus
  • Compute the extension of the cable using the formula ΔL = ε × L, where L is the original length of the cable
USEFUL FOR

Mechanical engineers, materials scientists, and students studying mechanics of materials will benefit from this discussion, particularly those involved in structural analysis and design of load-bearing systems.

ashicus
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(a) The steel cable to the hoist is 15m in length and has a diameter of 25mm. Its steel has a maximum permissible working stress of 200N/mm2 and a Young’s modulus of elasticity of 210,000N/mm2. The maximum load allowed on the hoist is 75kN. Determine the following:-
(i) the cross-sectional area of the cable
(ii) the tensile stress applied to the cable at maximum
load
(iii) whether the tensile stress is within permissible limits
(iv) the strain on the cable at maximum load
(v) the extension of the cable at maximum load.


Ive worked out the cross sectional area with the pie R2 rule but halved the 25mm to get the radius.

the exact answer that i got was pie X 12.5^2 = 490.8738521234052

i can't seem to find anywhere how to work out parts 2,3,4 or 5

can somebody help me please

Thanks

Ash
 
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Part one is right although 5 significant figures is enough for this calculation. Are you currently taking a mechanics of materials course? Are you familiar with the equation:

\sigma = \frac{F}{A}

If so, how do you think it applies to part 2?
 

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