"Determine working stress and greatest allowable load" 1. The problem statement, all variables and given/known data The maximum load in a tensile test on a mild steel specimen of diameter 12.5 mm is 95 kN, calculate the ultimate tensile stress. Also, determine the working stress and greatest allowable load on a rod of the same material 25 mm in diameter, given that the factor of safety is to be 3.5. 2. Relevant equations 3. The attempt at a solution I'm only in the first term of my course and still new to this. I believe i've worked out the ultimate tensile strength here; Pi x 6.25^2 = 122.718mm^2 95000/122.718 = 774.1326 now, where i'm struggling is the second two parts. Am i using the same force for this, the 95 kN or do i need to work out a new force using factor of safety and the new diameter? I know factor of safety = Stress at Failure/Max working stress. Greatest allowable load, is this the same as maximum load? What i have tried and found out to be wrong is; Pi x 12.5^2 = 490.87 95000/490.87 = 193.534 193.534/3.5 = 55.3 I'm not asking for the answer. Just a point in the right direction would be great. Thanks.