Calculate the Vertical Acceleration

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Northbysouth
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Homework Statement


Calculate the vertical acceleration a (positive if up, negative if down) of the 70-lb cylinder for each of the two cases illustrated. Neglect friction and the mass of the pulleys.

I have attached an image of the problem

Homework Equations





The Attempt at a Solution



I think I've managed to calculate part b:

ƩFy = may = 122lbf - 70lbf

ay = (122lbf - 70lbf)/(70/32.2)

ay = 23.92 ft/s2

But I'm unsure with part a. Initially I has thought they were the same scenario, but after looking at the practice example (the same scenario with the final answers but the numbers are different) I can see that ay is different in both scenarios. I can see how in situation a that the 122 lb force has an acceleration which is not present in situation b but I don't see how the the acceleration in the 122 lb block would impact the 70 lb block.

Help is appreciated
 
Attachments
  • Two pulley diagrams of a 70 lb cylinder and a 122 lb cylinder hung from ropes over pulleys, labelled case (a) with both cylinders hanging, and case (b) with the 70 lb cylinder on the left and the 122 lb weight pulled down by a red arrow on the right.
    dyn 3.011.png
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Northbysouth said:
I can see how in situation a that the 122 lb force has an acceleration which is not present in situation b but I don't see how the the acceleration in the 122 lb block would impact the 70 lb block.
You could think of it as the 122lb mass is 'using' some of the 122lbf acting on it for its own acceleration. So it is not all transmitted through the cable.
Let the tension in the cable be T. This is the same both sides (yes?). The acceleration is also the same both sides. That gives you two equations with the same two unknowns.