Finding when acceleration is zero

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SUMMARY

The discussion centers on calculating the value of x at which the acceleration of a block with a mass of 2.42 kg becomes zero while being accelerated by a tension of 13.9 N over a pulley. The coefficient of kinetic friction is 0.395, and the block's acceleration is given as 2.28 m/s². To determine when acceleration is zero, the net forces in both the x and y directions must be equal to zero, indicating a state of equilibrium.

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  • Understanding of Newton's laws of motion
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  • Concept of equilibrium in physics
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alexi_b
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Homework Statement


A block of mass 2.42kg is accelerated across a rough surface by a rope passing over a pulley, as shown in the figure below. The tension in the rope is 13.9N, and the pulley is 12.3cm above the top of the block. The coefficient of kinetic friction is 0.395.

A: 2.28 m/s^2

Calculate the value of x at which the acceleration becomes zero. <-- this is what I'm stuck on


Homework Equations

The Attempt at a Solution


I know when acceleration is equal to zero, it means that the forces in the x and y direction are equal to zero, but that is as far as i know of how I can complete this. Any suggestions?
 
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alexi_b said:

Homework Statement


A block of mass 2.42kg is accelerated across a rough surface by a rope passing over a pulley, as shown in the figure below. The tension in the rope is 13.9N, and the pulley is 12.3cm above the top of the block. The coefficient of kinetic friction is 0.395.

A: 2.28 m/s^2

Calculate the value of x at which the acceleration becomes zero. <-- this is what I'm stuck on


Homework Equations

The Attempt at a Solution


I know when acceleration is equal to zero, it means that the forces in the x and y direction are equal to zero, but that is as far as i know of how I can complete this. Any suggestions?
I don't know what x stands for, but you have to find when the net force is zero, as you said. Without a figure, it is hard to help
 

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