Calculate the wave speed in each string

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The discussion focuses on calculating wave speeds in two strings with different linear densities under the tension of a 500 g mass. For string 1 with a linear density of 2.30 g/m and string 2 with 4.10 g/m, the wave speeds need to be determined using the formula that incorporates tension and linear density. A user questions why the speed in string 1 is not calculated using the formula involving the gravitational force on the mass, clarifying that mass should not be confused with force. The conversation emphasizes the importance of correctly applying physical principles to avoid confusion in calculations. Accurate calculations are essential for understanding wave dynamics in different string conditions.
nick85
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In Fig. 17-30a, string 1 has a linear density of 2.30 g/m, and string 2 has a linear density of 4.10 g/m. They are under tension owing to the hanging block of mass M = 500 g.



(a) Calculate the wave speed in each string.
m/s (speed in string 1)
m/s (speed in string 2)

(b) The block is now divided into two blocks (with M1 + M2 = M) and the apparatus rearranged as shown in Fig. 17-30b. Find M1 and M2 such that the wave speeds in the two strings are equal.
g (mass of M1)
g (mass of M2)

why wouldn't the speed in string 1 be given by the sqr root of (500*9.8)/(4.1)?

Thanks for any help.
 
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A mass of 500g is five hundred grams not five hundred times g. Remember mass is not a force.

-Hoot
 

Thread 'Magnitude of buoyant force in fluids of different densities'

The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?
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