Calculate the wave speed in each string

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SUMMARY

The discussion focuses on calculating the wave speed in two strings with different linear densities: string 1 at 2.30 g/m and string 2 at 4.10 g/m, both under a tension from a 500 g mass. The wave speed in each string can be determined using the formula \( v = \sqrt{\frac{T}{\mu}} \), where \( T \) is the tension and \( \mu \) is the linear density. Additionally, the discussion addresses how to adjust the masses M1 and M2 so that the wave speeds in both strings are equal, emphasizing the importance of understanding mass versus force in these calculations.

PREREQUISITES
  • Understanding of wave mechanics and wave speed calculations
  • Familiarity with linear density and its impact on wave propagation
  • Knowledge of tension in strings and its relationship to mass
  • Basic grasp of Newton's laws, particularly the distinction between mass and force
NEXT STEPS
  • Study the wave speed formula \( v = \sqrt{\frac{T}{\mu}} \) in detail
  • Explore the effects of linear density on wave propagation in different mediums
  • Investigate the principles of tension in strings and its calculation
  • Learn about the relationship between mass and force in physics
USEFUL FOR

Physics students, educators, and anyone interested in wave mechanics and string dynamics will benefit from this discussion.

nick85
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In Fig. 17-30a, string 1 has a linear density of 2.30 g/m, and string 2 has a linear density of 4.10 g/m. They are under tension owing to the hanging block of mass M = 500 g.



(a) Calculate the wave speed in each string.
m/s (speed in string 1)
m/s (speed in string 2)

(b) The block is now divided into two blocks (with M1 + M2 = M) and the apparatus rearranged as shown in Fig. 17-30b. Find M1 and M2 such that the wave speeds in the two strings are equal.
g (mass of M1)
g (mass of M2)

why wouldn't the speed in string 1 be given by the sqr root of (500*9.8)/(4.1)?

Thanks for any help.
 
Physics news on Phys.org
A mass of 500g is five hundred grams not five hundred times g. Remember mass is not a force.

-Hoot
 

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