Calculate the wavelength of an electron traveling at 1.12*10^5m/s

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Discussion Overview

The thread discusses the calculation of the wavelength of an electron traveling at a specified speed of 1.12*10^5 m/s. The scope includes homework-related assistance and the application of quantum mechanics principles.

Discussion Character

  • Homework-related

Main Points Raised

  • One participant requests the wavelength to be expressed in meters.
  • Another participant suggests that the original poster should attempt the problem independently.
  • A participant expresses confusion about the problem and seeks help from others.
  • One participant claims to have solved the problem, stating the wavelength is 0.649*10^-8 meters.
  • A reminder is given that assistance requires showing an attempt at solving the problem.
  • Another participant confirms that meters is the correct unit for the answer.
  • A participant later indicates they have figured out the problem on their own.

Areas of Agreement / Disagreement

There is no consensus on the solution, as multiple participants express varying levels of understanding and engagement with the problem. Some participants emphasize the need for independent effort before seeking help.

Contextual Notes

The discussion reflects varying levels of understanding among participants, with some providing answers while others seek clarification. There are no detailed calculations or methodologies presented for the wavelength calculation.

Who May Find This Useful

Students seeking assistance with quantum mechanics problems, particularly those related to the de Broglie wavelength of particles.

plstevens
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answer should be in meters.

lamda=_______m
 
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do your own homework
 
uh, i don't understand it or i would but thanks for all your help! But if someone else could please help me with this problem that would be greatly appreciated
 
i just got it, it's 0.649*10^-8.
 
If you want help from anyone in here, you have to show an attempt.

Read the rules.
 
meters is the unit, by the way
 
well thanks anyway but i figured it out.
 

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