1. The problem statement, all variables and given/known data A force Fx acts on a particle that has a mass of 1.46 kg. The force is related to the position x of the particle by the formula Fx = Cx^3, where C = 0.550 if x is in meters and Fx is in newtons. Calculate the work done by this force on the particle as the particle moves from x = 2.96 m to x = 1.47 m. 2. Relevant equations W = F.x Where F is the force and x is the displacement 3. The attempt at a solution The displacement x = 1.47-2.96 = -1.49m The force Fx = Cx^3 = (0.550)(-1.49)^3 = -1.82 (to 3 significant figures) Input these values into the formula, W=F.x W = (-1.82)(-1.49) = 2.71 Joules (to 3 significant figures) This is the answer I get however it's not the expected answer. Could someone please point me in the right direction, so I can understand where I am going wrong.