Calculate time to raise temperature of water

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SUMMARY

The discussion centers on calculating the time required to raise the temperature of water using heat capacity and specific heat capacity. The user initially confuses the two concepts but clarifies that heat capacity refers to the energy required to change the temperature of an object, while specific heat capacity pertains to the energy needed to change the temperature of a unit mass of a substance. The final formula established is Time = (Energy to heat water + Energy to heat kettle) / Power input, where Energy to heat kettle is calculated using its heat capacity and the change in temperature.

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  • Understanding of heat capacity and specific heat capacity
  • Basic knowledge of thermodynamics principles
  • Familiarity with the formula for energy transfer (Q = mcΔT)
  • Knowledge of power calculations (P = IV)
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  • Research the differences between heat capacity and specific heat capacity
  • Learn how to calculate energy transfer in thermodynamic systems
  • Explore practical applications of calorimetry in experiments
  • Study the relationship between power, energy, and time in heating processes
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Students in physics or engineering, educators teaching thermodynamics, and anyone involved in practical applications of heat transfer calculations.

polyperson
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The problem I have is in understanding what is meant by heat capacity (as opposed to specific heat capacity).

I have been given the heat capacity (J kg-1) of a kettle plus the power input (IV), the mass of water and given that the water must be raised from room temp to boiling point.

The question asked is how long will this take.

I know that Specific Heat Capacity = I V t / m (change in temp) but where does the heat capacity come in all of this?

Any help appreciated!
 
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Well, a specific heat capacity is in J/kg*C while your heat capacity is simply in J/C. It's called a heat capacity basically when you're just using an object as opposed to different masses. For example, I'd use a crucible as a calorimeter that has a heat capacity of 180J/C because the mass doesn't change, its simply an object whose mass remains constant.
 
Thanks peng. I can understand that part - I just can't see how it fits into the calculation. The way I see it:

The energy required to heat the water = mass x specific heat capacity of water x change in temp

And:

Time to change temp = Energy required / Power input

I know this is not correct but I don't know why
 
Well remember... the water isn't the only thing being heated up...
 
Yes, I see where you are coming from now. I need to think about it some more.
 
Time = (Energy to heat water + Energy to heat kettle) / Power input

Energy to heat kettle = Heat capacity x change in temp ?
 
exactly!

good job.
 
Thanks peng. I got there in the end!
 

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