Calculate Transition in Hydrogen for 600nm Wavelength

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Discussion Overview

The discussion revolves around calculating a possible electronic transition in hydrogen that corresponds to a wavelength of approximately 600 nm, utilizing the Rydberg formula and related energy equations. The scope includes homework-related problem-solving and mathematical reasoning.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant attempts to use the Rydberg formula and related equations to find a transition corresponding to the given wavelength, calculating frequency and energy values.
  • Another participant points out that the Rydberg formula involves two integers, suggesting a misunderstanding in the application.
  • A different participant infers that negative results indicate emission rather than absorption, adding a layer of interpretation to the calculations.
  • Some participants express that they have not yet learned the Rydberg constant or the full Rydberg formula, indicating a potential gap in knowledge relevant to the problem.
  • One participant calculates energy changes using a different approach and arrives at a non-integer value for the principal quantum number, questioning their method and seeking clarification on the error.

Areas of Agreement / Disagreement

Participants exhibit disagreement regarding the correct application of the Rydberg formula and the interpretation of negative energy results. There is no consensus on the correct approach to solving the problem, and multiple viewpoints are presented.

Contextual Notes

Limitations include the participants' varying levels of familiarity with the Rydberg constant and the Rydberg formula, as well as unresolved mathematical steps in the calculations presented.

Who May Find This Useful

Students learning about atomic transitions, the Rydberg formula, and energy calculations in quantum mechanics may find this discussion relevant.

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Homework Statement


use the RYDBERG formula to suggest a possible transition that would result in the observed wavelength


Homework Equations


Hydrogen - yellow wavelength about 600nm


The Attempt at a Solution


I used c= lambda x frequency(V) and found (V) to equal 5e14/second
I then used energy(E) = constant(h) x V and found E to equal 3.32e-19j
Last i used En = (-2.178e-18j)/n^2 to find the transition, I did 3.32e-19j = (-2.178e-18j)/n^2 and found n^2 to equal -6.57014 and I'm stuck there because it's a negative number...
 
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Rydberg formula contains two integers, not one.

What is Rydberg constant value?
 
I believe negative results infer emission rather than absorption.
 
That formula finds the principle energy level, not the energy emission or absorption
 
We haven't learned rydbergs constant yet, so I was assuming we used the one I posted
 
we haven'y learned that formula yet, he told us to use E(n) = (-2.178x10^-18)/n^2
 
ok well i did (change in energy) = E(f) - E(i)
delta(E) = 3.3e-19
E(f) = En when n=2
When n=2 E= -5.445e-19
so 3.3e-19 = -5.445e-19 - E(i)
E(i) = -8.745e-19
I then used E(i) = -2.178e-18/n2
i got n= 1.57815 which doesn't make sense, can anyone tell me what i did wrong?
 

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