Calculate Velocity of 10kg Block on Incline Plane | Work-Energy Theorem

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Homework Help Overview

The discussion revolves around calculating the velocity of a 10kg block being pulled up a 30-degree incline over a distance of 5.0m, using the work-energy theorem. Participants are examining the forces acting on the block, including applied force, gravitational force, and friction.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants are discussing the application of the work-energy theorem, questioning the forces at play, and clarifying the setup of the problem. There are inquiries about the initial conditions, such as whether the velocity is zero at the start and the nature of the applied force.

Discussion Status

There is an ongoing exploration of the calculations related to work done by various forces and how they contribute to the kinetic energy of the block. Some participants are confirming the correctness of the work done calculations and questioning the provided answer for velocity.

Contextual Notes

Participants are correcting terminology, specifically regarding kinetic friction, and are noting the importance of understanding the total work done in relation to energy changes in the system. There is a lack of explicit consensus on the final velocity calculation, with some suggesting that the given answer may be incorrect.

ms.cupcake
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10kg block is pulled up an incline plane at 30 degree with horizontal in distance 5.0m by force 120N.coefficient of kinetic energy 0.4.

help!how do you get the velocity of block? answer: v=3.48ms^-1
 
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Are you looking for the velocity at 5m with velocity = 0 at 0m? Or what?
 
the velocity of the block after it has move 5m up the plane
 
ms.cupcake said:
10kg block is pulled up an incline plane at 30 degree with horizontal in distance 5.0m by force 120N.coefficient of kinetic energy 0.4.
I assume you meant that the coefficient of kinetic friction is 0.4.

So what does the work-energy theorem say? What forces are acting on the block? How much work do they do?
 
*correction- kinetic friction*.
frictional force,the gravitational force,applied force and normal force.The work done by gravitational force=-245.25J,energy lost by overcoming friction=-169.92J,work done by force,120N=600J, and the total work done i found was 184.83J. so how do I get the velocity of the block after it has move 5m up the plane?
 
Last edited:
ms.cupcake said:
*correction- kinetic friction*.
frictional force,the gravitational force,applied force and normal force.The work done by gravitational force=-245.25J,energy lost by overcoming friction=-169.92J,work done by force,120N=600J, and the total work done i found was 184.83J. so how do I get the velocity of the block after it has move 5m up the plane?
Assuming you've calculated the total work correctly, use the work-energy theorem! Total Work = ΔKE.
 
ms.cupcake said:
10kg block is pulled up an incline plane at 30 degree with horizontal in distance 5.0m by force 120N.coefficient of kinetic energy 0.4.

help!how do you get the velocity of block? answer: v=3.48ms^-1
I don't see how you can get that answer from the given data.

Is the applied force parallel to the incline?

If this from a textbook, tell me which book and problem.
 
applied force is parallel.
and no its not from txtbook
 
Last edited:
ms.cupcake said:
*correction- kinetic friction*.
frictional force,the gravitational force,applied force and normal force.The work done by gravitational force=-245.25J,energy lost by overcoming friction=-169.92J,work done by force,120N=600J, and the total work done i found was 184.83J. so how do I get the velocity of the block after it has move 5m up the plane?

work in = friction loss + gain in potential energy + gain in kinetic energy.

You are very close to solving this problem. Your numbers agree with mine. So where do the 185 J go at the top of the ramp?

BTW I believe the given answer is wrong if v = 0 at the bottom of the ramp.
 

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