Calculate Velocity of Skydiver: Mass M, Air Drag Coefficient D

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SUMMARY

The discussion focuses on calculating the velocity of a skydiver with a mass of 80 kg and an air drag coefficient of 0.1 kg/m. The participant initially calculated the terminal velocity (Vt) as 88.5 m/s using the formula Vt = √(mg/D). However, they encountered difficulties applying the correct high-speed air drag formula, which differs from the low-speed drag derivation provided in their textbook. The correct approach involves solving the differential equation m*(dv/dt) = mg - Dv² to find the velocity as a function of time.

PREREQUISITES
  • Understanding of differential equations
  • Knowledge of physics concepts related to forces and motion
  • Familiarity with air drag principles, specifically quadratic drag
  • Basic calculus skills for solving differential equations
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  • Study the derivation of the velocity function for high-speed air drag
  • Learn how to solve first-order differential equations
  • Explore the concept of terminal velocity in different drag scenarios
  • Review the application of separation of variables in differential equations
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Physics students, engineers, and anyone interested in understanding the dynamics of free fall and air resistance in skydiving scenarios.

Crebble32
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Calculate velocity of the skydiver of mass M= 80kg as a function of time. The air drag coefficient D= 100g/m = 0.1kg/m. Assume that the skydiver has v=o at t=0.


In my book high speed air drag is f=Dv^2.
I found Vt= 88.5 m/s with Sqrt(mg/D). BUT this is not the V they are asking for :(

my book derives the formula for V with the low speed air drag, not the HIGH speed one. I can't follow the steps they did and figure out what exactly the formula actually is! What I started out with is:

m*(dv/dt) = mg- Dv^2

I have no clue where to go from here :( If anyone could help me I appreciate any help I can get!
 
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