Calculate Water Depth Using Sonar | Speed of Sound = 5300 km/h

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SUMMARY

The discussion focuses on calculating water depth using sonar, given the speed of sound in water at 5300 km/h and an echo return time of 870 ms. The correct approach involves converting milliseconds to seconds and then calculating the distance using the formula distance = speed × time. The final depth calculation yields 0.64 km, confirming that unit conversions are crucial for accurate results.

PREREQUISITES
  • Understanding of basic physics concepts, specifically sound propagation.
  • Familiarity with unit conversions, particularly between milliseconds, seconds, and hours.
  • Knowledge of the formula for calculating distance: distance = speed × time.
  • Ability to manipulate units in calculations, including converting km/h to m/s.
NEXT STEPS
  • Learn about unit conversion techniques in physics, focusing on time and distance.
  • Study the principles of sonar technology and its applications in underwater depth measurement.
  • Explore the speed of sound in different mediums and how it affects measurement accuracy.
  • Investigate common errors in physics calculations and how to avoid them.
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Students in physics courses, educators teaching sound propagation concepts, and professionals utilizing sonar technology for underwater measurements.

dlre
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Please help! trying to catch up with class! topic: the speed of sound

Homework Statement



Determine the depth of water if an echo using sonar returns in 870 ms and the speed of sound in water is 5300 km/h.

Homework Equations



distance= speed * time
depth=distance/2

The Attempt at a Solution


time= 870s
speed= 5300km/h

--------
i'm stuck at the part on converting ms to h. i think the

the answer i got is 0.64km

870ms= 0.00024167h
distance = 5300*0.00024167 = 1.28
depth= 1.28/2 = 0.64
 
Last edited:
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Will it take some time to come back?
 
i really have no idea. i missed two months of physics and now struggling.

i think it took 870 ms to return.
 
ms means mili second and mili is 10^-3?
 
All units must be in same system (SI).

length in meter
time in second
 
is km/hour is SI unit of velocity?
 
isn't it?

does it matter?

if we'redoing this by meter and second, then this is my attempt

d= 5300000m/s *0.87 s = 4,611,000m
depth= 4,611,000/2 = 2,305,500

--------
 
did you converted hour in sec?? it will be 5300*1000/3600 m/s
 
i give up. I'm going to bed!

good night! thanks for helping
 
  • #10
d = v*t = (5300*1000/3600) m/s*(870/1000) s =
 
  • #11
Your answer of .64km looks good to me (and seems like a reasonable depth). So this question seems to be mainly about unit conversions.
Start with 870 ms . Now we know that ms means milliseconds, and that milli means 10^-3
So 870 ms = 870 x 10^-3 s = .87 s

Or another way to think about this is to multiply the 870ms with the correct ratios to cancel out the ms units so that you are left with seconds :

870 ms x \frac{1s}{1000ms} = .87s
Here you are left with seconds; as you can see the milliseconds have canceled out.

You could continue to convert this into hours:

.87s x \frac{1 min}{60s} x \frac{1 hr}{60 min} = 2.416...x 10^-4 hr
Here we are left with hours since the units of seconds and minutes have been eliminated.

Now for the question:

\frac{5300 km}{1 hr} x \frac{1000 m}{1 km} x \frac{1 hr}{60 min} x \frac{1 min}{60 s} = \frac{1472.222 m}{1 s}

\frac{1472.222 m}{1 s} x .87s = 1280.83 m

1280.83 / 2 = 640.4 m or .64 km
 

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