Calculate Water Depth Using Sonar | Speed of Sound = 5300 km/h

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Homework Help Overview

The discussion revolves around calculating the depth of water using sonar, given the speed of sound in water and the time taken for an echo to return. The subject area includes concepts of sound speed, distance, and time in the context of physics.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss unit conversions, particularly converting milliseconds to seconds and kilometers per hour to meters per second. There are attempts to clarify the relationship between distance, speed, and time, as well as the implications of using different units.

Discussion Status

Participants are actively engaging with the problem, exploring various interpretations of the units involved. Some guidance on unit conversion has been provided, and there is a recognition of the importance of consistent units in calculations. However, there is no explicit consensus on the final depth calculation.

Contextual Notes

There is mention of missing class time, which may contribute to some participants' uncertainty. The discussion also highlights the necessity of using SI units for consistency in calculations.

dlre
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Please help! trying to catch up with class! topic: the speed of sound

Homework Statement



Determine the depth of water if an echo using sonar returns in 870 ms and the speed of sound in water is 5300 km/h.

Homework Equations



distance= speed * time
depth=distance/2

The Attempt at a Solution


time= 870s
speed= 5300km/h

--------
i'm stuck at the part on converting ms to h. i think the

the answer i got is 0.64km

870ms= 0.00024167h
distance = 5300*0.00024167 = 1.28
depth= 1.28/2 = 0.64
 
Last edited:
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Will it take some time to come back?
 
i really have no idea. i missed two months of physics and now struggling.

i think it took 870 ms to return.
 
ms means mili second and mili is 10^-3?
 
All units must be in same system (SI).

length in meter
time in second
 
is km/hour is SI unit of velocity?
 
isn't it?

does it matter?

if we'redoing this by meter and second, then this is my attempt

d= 5300000m/s *0.87 s = 4,611,000m
depth= 4,611,000/2 = 2,305,500

--------
 
did you converted hour in sec?? it will be 5300*1000/3600 m/s
 
i give up. I'm going to bed!

good night! thanks for helping
 
  • #10
d = v*t = (5300*1000/3600) m/s*(870/1000) s =
 
  • #11
Your answer of .64km looks good to me (and seems like a reasonable depth). So this question seems to be mainly about unit conversions.
Start with 870 ms . Now we know that ms means milliseconds, and that milli means 10^-3
So 870 ms = 870 x 10^-3 s = .87 s

Or another way to think about this is to multiply the 870ms with the correct ratios to cancel out the ms units so that you are left with seconds :

870 ms x \frac{1s}{1000ms} = .87s
Here you are left with seconds; as you can see the milliseconds have canceled out.

You could continue to convert this into hours:

.87s x \frac{1 min}{60s} x \frac{1 hr}{60 min} = 2.416...x 10^-4 hr
Here we are left with hours since the units of seconds and minutes have been eliminated.

Now for the question:

\frac{5300 km}{1 hr} x \frac{1000 m}{1 km} x \frac{1 hr}{60 min} x \frac{1 min}{60 s} = \frac{1472.222 m}{1 s}

\frac{1472.222 m}{1 s} x .87s = 1280.83 m

1280.83 / 2 = 640.4 m or .64 km
 

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