The discussion revolves around calculating the x-intercept of the linear function f(x) = 0.02605x - 0.01908. Participants are exploring the implications of this calculation and verifying the accuracy of their results.
Some participants have confirmed their calculations, while others are seeking clarification on the notation and the process of verification. There is an ongoing exploration of the implications of rounding in the context of the calculations.
There is a noted lack of familiarity with the function notation among some participants, which may influence their understanding of the problem. Additionally, the discussion includes considerations about the precision of the calculated x-intercept.
rollcast said:Homework Statement
f(x) =0.02605x-0.01908
Calculate the x-axis intercept for the function above.
Homework Equations
f(x) =0.02605x-0.01908
The Attempt at a Solution
0 = 0.02605x - 0.01908
0.02605x = 0.01908
x = 0.732 (3 s.f.)
Mark44 said:What's your question?
I can see that you did that, but what is your question?rollcast said:I'm trying to calculate the x - intercept of the line, f(x) =0.02605x-0.01908.
Mark44 said:I can see that you did that, but what is your question?
jedishrfu said:looks right, I got 0.7324 to 4 sig figures
Just check it by plugging in it into thee original eqn to verify that f(x) is zero.