Finding the X-intercept of a function

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Homework Help Overview

The discussion revolves around finding the X-intercept of the function F(x) = x - 12x^(1/3). Participants are exploring the implications of setting the function equal to zero to identify the X-intercept.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the method of u-substitution, where u = x^(1/3), transforming the equation into a cubic form. There are questions about whether to cube the constant term -12 and how that affects the solution. Some participants express confusion about the teacher's answer of ±24√3 and seek clarification on the steps leading to that result.

Discussion Status

The conversation is active, with participants providing insights on the u-substitution method and discussing the implications of cubing terms. There is no explicit consensus on the approach to take, but guidance has been offered regarding the use of u-substitution and the interpretation of the function's behavior.

Contextual Notes

Participants are working under the constraints of homework rules, which may limit the extent of assistance they can receive. There is an emphasis on understanding the reasoning behind each step rather than simply arriving at the answer.

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Homework Statement


F(x)= x-12x1/3 Find the X-intercept

Homework Equations


X-intercept means y=0

The Attempt at a Solution


My math teacher gave plus or minus 24sqrt3 as an answer, but I have no idea how he got that! He also got 0, but I do understand that one... I just don't know how to get the 24sqrt3 Could someone help me, please?
 
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Airp said:

Homework Statement


F(x)= x-12x1/3 Find the X-intercept

Homework Equations


X-intercept means y=0

The Attempt at a Solution


My math teacher gave plus or minus 24sqrt3 as an answer, but I have no idea how he got that! He also got 0, but I do understand that one... I just don't know how to get the 24sqrt3 Could someone help me, please?

Set ##u = x^{1/3}##, so your equation becomes ##0 = u^3 - 12 u##, or ##0 = u(u^2-12)##.
 
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Thank You! Quick question: since you put everything to the cube, should you put -12 also to the power three, because that's how I finally got the answer! Thank you so much!
 
The u-substitution is all you need. However, the answer you get is for u. x = u^3. So you will cube your answer.
There should be no reason to cube 12. That would be assuming that
##F(x)^3=(x-12x^{1/3})^3 = x^3 - 12^3 x## but that is not how powers of polynomials work.
Edit:
However, in this case, since you are assuming that F(x) = 0 (x- intercept), you will get the right solution since:
##0=x-12x^{1/3}##
##x=12x^{1/3}##
##x^3=12^3x##
##0=x^3-12^3x##
There are many ways to get to the answer...just be sure you know why you are doing things.
 
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RUber said:
The u-substitution is all you need. However, the answer you get is for u. x = u^3. So you will cube your answer.
There should be no reason to cube 12. That would be assuming that
##F(x)^3=(x-12x^{1/3})^3 = x^3 - 12^3 x## but that is not how powers of polynomials work.
Edit:
However, in this case, since you are assuming that F(x) = 0 (x- intercept), you will get the right solution since:
##0=x-12x^{1/3}##
##x=12x^{1/3}##
##x^3=12^3x##
##0=x^3-12^3x##
There are many ways to get to the answer...just be sure you know why you are doing things.
Thank you so much! This community really is awesome!
 

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