Calculating absolute magnitude and apparent magnitude

Click For Summary
SUMMARY

The discussion centers on calculating the absolute magnitude of Proxima Centauri using its parallax angle and apparent bolometric magnitude. The formula m - M = 5 log10(d/10 pc) is utilized, where d is derived from the parallax angle of 0.769". The apparent bolometric magnitude of 11.1 is confirmed as the necessary value for m, clarifying the distinction between bolometric and visual magnitudes. This resolution allows for the calculation of absolute magnitude without further complications.

PREREQUISITES
  • Understanding of parallax angle in astronomy
  • Familiarity with the concept of absolute and apparent magnitude
  • Knowledge of logarithmic functions
  • Ability to apply the distance modulus formula
NEXT STEPS
  • Study the differences between bolometric and visual magnitudes
  • Learn how to calculate distance using parallax measurements
  • Explore the implications of absolute magnitude in stellar classification
  • Investigate the use of the distance modulus in various astronomical contexts
USEFUL FOR

Astronomy students, astrophysics enthusiasts, and anyone interested in stellar measurements and calculations.

dalai_lala
Messages
1
Reaction score
0
Ummm... never mind, we found it...

Homework Statement



Given Proxima Centauri with parallax angle of 0.769" and apparent bolometric magnitude of 11.1... what is its absolute magnitude?

Homework Equations



I get that I should use m-M = 5 log10(d/10 pc) and I understand that d = 1/p".

What I really need to know is: what do I use to get apparent magnitude? After I get m I can plug and chug, and I'm fine with that... but how do I get m?

Apparent magnitude was not given and I can't look it up for a quiz or test.

The Attempt at a Solution



so far...

m-M = 5 log10 [(1/0.769)/10]

or M = m - 5 log10 (.1300)

But I'm still stuck on where to go for m...

Thanks!

Lori the Totally Lost English Major
 
Last edited:
Physics news on Phys.org
They gave you the "apparent bolometric magnitude", just use that. The only difference between that and "apparent visual magnitude" is what wavelengths of light are being measured.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
5K
  • · Replies 1 ·
Replies
1
Views
6K
Replies
6
Views
3K
  • · Replies 4 ·
Replies
4
Views
3K
Replies
6
Views
3K
  • · Replies 8 ·
Replies
8
Views
1K
  • · Replies 5 ·
Replies
5
Views
4K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 8 ·
Replies
8
Views
2K