Calculating Acceleration and Angle on a Frictionless Air Track

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To calculate the acceleration of a cart on a frictionless air track, the formula a = 2d/t² can be used, where d is the distance traveled and t is the time elapsed. Given that the cart travels 32.0 cm in 2.0 seconds, the acceleration can be calculated as a = 2(0.32 m)/(2.0 s)², resulting in an acceleration of 0.08 m/s². The angle of the track can be determined using the relationship a = g sin(θ), where g is the acceleration due to gravity. By substituting the known values, the angle θ can be calculated. The problem was successfully solved with this guidance.
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Please help me with this question. I understand how to calculate the velocity from the given conditions but I don't know how to figure out the acceleration or the angle. Thanks!

A cart is released from rest at the top of a perfectly frictionless air track. After an elapsed time delta t = 2.0s, the cart has traveled delta x = 32.0 cm down the track. What is the cart's acceleration? What is the angle of theta of this track?
 
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The acceleration of the cart is the component of its weight parallel to the track divided by its mass so a = g \cos \theta. The distance it travels is

d = \frac {1}{2} a t^2

and you have enough information to find the acceleration and the angle.
 
I've figured out the problem with your help. Thank you!
 
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