Calculating Acceleration and Final Speed of a Car with a Given Force and Mass

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SUMMARY

The discussion focuses on calculating the acceleration and final speed of a car using Newton's Second Law and kinematic equations. Given a force of 5.0 x 10³ N applied to a car with a mass of 1.1 x 10³ Kg for 6.0 seconds, the acceleration can be calculated using the formula F = m * a, resulting in an acceleration of approximately 4.55 m/s². The final speed can be determined using the equation v = u + at, yielding a final speed of 27.3 m/s. The discussion also highlights that a greater mass, such as 1.4 x 10³ Kg, would result in a longer time to reach the same speed due to the inverse relationship between mass and acceleration as stated in Newton's Second Law.

PREREQUISITES
  • Understanding of Newton's Second Law (F = m * a)
  • Familiarity with kinematic equations (SUVAT equations)
  • Basic knowledge of force, mass, and acceleration
  • Ability to perform unit conversions and calculations
NEXT STEPS
  • Learn how to apply Newton's Second Law in various scenarios
  • Study kinematic equations in-depth, focusing on the SUVAT equations
  • Explore the effects of mass on acceleration and speed in different contexts
  • Practice solving problems involving force, mass, and acceleration
USEFUL FOR

Students studying physics, automotive engineers, and anyone interested in understanding the principles of motion and force calculations.

flower123
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Really desperate for some help with this, Thought i had i cracked and quite clearly i don't
Im very bad with explaining how i arrived at a answer as i make such a mess of my answers and some time just guess as i can't seem to figure it out! Please help
. What is the magnitude of the acceleration that this force will cause when applied to a car with a mass of 1.1x10³Kg

Then calculate the final speed of the car (above) assuming that it was standing still initially and that the force of 5.0 x 10³ N is applied for 6.0s

Why would the car take longer to reach the calculated speed if the car's mass was 1.4 x10³Kg. which part of Newtons second law would explain this.

THANKS in advance .
 
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Say flower, why don't you write out the equation for Newton's 2nd law, and the kinematic motion equations, and play around with them for a few minutes, and see what you get. Please show your work and post your results. Then someone will check it for you and provide further assistance.
 
As my mechanics teacher always says - Write down what you know first.

Force (F) =
Time (t) =
Mass (m) =
Initial Speed (u) =

You know what all the above are, so fill them in.

Acceleration (a) =
Final Speed (v) =

What equations can you think of relating the 4 above quantities with the above 2 values? As Jay said, think suvat (the one without s as you don't know that) and Newton's 2nd law.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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