Calculating Acceleration from Change in Velocity and Distance

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To calculate the acceleration of an electron that changes its velocity from 1.0 x 10^4 m/s to 4.0 x 10^6 m/s over a distance of 1 cm, the average velocity can be determined first. The average velocity is (initial velocity + final velocity) / 2, which helps in calculating the time taken to traverse the 1 cm distance. Using the kinematic equation v^2 = u^2 + 2ax, the acceleration can be isolated and calculated. The time can also be derived from the average velocity and the distance. This approach effectively combines kinematic principles to find the required acceleration.
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An electron with initial velocity v_{x}_{o} = 1.0 \times 10^{4} meters/sec enters a region where it is electrically accelerated. It emerges with a velocity v_{x} = 4.0 \times 10^{6} meters/sec. What was its acceleration, assumed constant? The accelerated region is 1 cm. So acceleration is defined as \frac{\Delta v}{\Delta t}. How would I use the fact that the accelerated region is 1 cm long?

Thanks
 
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Calculate the time it takes for the electron to traverse that distance. (Hint: What's the average velocity?)

You can also make use of any formulas you may know describing the kinematics of uniformly accelerated motion.
 
use v^2 = u^2 + 2*a*x
where v = final velocity
u = initial velocity
a = acceleration
x = distance.
 
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