Calculating Acceleration & Initial Velocity from Displacement, Time & Final Velocity

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Homework Help Overview

The discussion revolves around calculating acceleration and initial velocity from given values of displacement, time, and final velocity, within the context of kinematics.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to rearrange kinematic equations to solve for acceleration and initial velocity but expresses difficulty in doing so. Some participants suggest alternative equations and substitutions to find the unknowns.

Discussion Status

Participants are exploring various approaches to the problem, with some suggesting substitutions and alternative equations. There is an ongoing exchange of ideas, but no explicit consensus has been reached on a single method.

Contextual Notes

There is a noted challenge due to the initial velocity being unknown, which complicates the application of the equations. The discussion includes attempts to derive relationships between the variables based on the provided information.

pavadrin
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hey,
I’ve been wondering for quite sometime now that if I am given values for displacement, time, and final velocity if it were able to calculate the acceleration and the initial velocity? I have been trying to rearrange the formulas:

v = u + at

v^2 = u^2 + 2as

s = ut + .5at^2

but have been unsuccessful. I would like to know if it were possible to calculate the unknowns using the values given, thanks,
Pavadrin
 
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From the first equation:
a = \frac{v-u}{t}

Substitute to the third.
 
Päällikkö said:
From the first equation:
a = \frac{v-u}{t}

Substitute to the third.
That still wouldn't be helpful seeing the initial velocity is unknown, what would be helpful is another equation:

s = t \frac{v+u}{2}

And transpose to give

u = \frac{2s}{t} - v

There is another way to calculate a as well using the 3rd formula, make ut = vt and - the .5at^2. Which will give you the right answer, you can test it by substituing fake values in.
 
Random333 said:
That still wouldn't be helpful seeing the initial velocity is unknown
Sure it would.
Making the substitution:

s = ut + \frac{1}{2}(v-u)t

u = 2 \frac{s}{t} - v
 
Päällikkö said:
Sure it would.
Making the substitution:

s = ut + \frac{1}{2}(v-u)t

u = 2 \frac{s}{t} - v
Ah, of course.
 
okay thanks for the help everyone :smile:
 

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