Calculating Acceleration of Skateboarder on 11.9m Ramp

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SUMMARY

The discussion focuses on calculating the acceleration of a skateboarder rolling down an 11.9-meter ramp, reaching a speed of 6.77 m/s at the bottom. To determine the magnitude of her acceleration, users are advised to utilize kinematic equations, specifically the equation \( v^2 = u^2 + 2as \), where \( v \) is the final velocity, \( u \) is the initial velocity, \( a \) is acceleration, and \( s \) is distance. Additionally, the component of acceleration parallel to the ground can be derived by resolving the total acceleration into horizontal and vertical components based on the ramp's incline of 29.8 degrees.

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  • Kinematic equations in physics
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  • Concept of inclined planes in physics
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Homework Statement


A skateboarder, starting from rest, rolls down a 11.9-m ramp. When she arrives at the bottom of the ramp her speed is 6.77 m/s. (a) Determine the magnitude of her acceleration, assumed to be constant. (b) If the ramp is inclined at 29.8 ° with respect to the ground, what is the component of her acceleration that is parallel to the ground?




The Attempt at a Solution



I don't even have a clue where to start? How can i figure out the magnitude of acceleration without the time?? And i dnt even understand what the second part is asking at all?

Any help on where to start is appreciated..
 
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I don't even have a clue where to start? How can i figure out the magnitude of acceleration without the time??
You may not have the time, but you have the distance. Take a closer look at your kinematic equations.

And i dnt even understand what the second part is asking at all?
Since she is accelerating down the ramp (so at an angle with the ground). You can resolve her acceleration into horizontal and vertical components.
 

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