Hi, I know the acceleration of steel ball rolling down the inclined track is 5/7 * gsin(theta). But is it possible to find the acceleration of ball rolling on the inclined track just by using the distance travelled on the horizontal plane(attached to the Inclined track) and the time taken? Assuming constant velocity and no friction when rolling on the horizontal plane.
vf^2 = vi^2 +2as -- 1
v(diagonal) = v(horizontal)/cos(theta) -- 2
The Attempt at a Solution
As we know that the speed along the horizontal plane is constant, the velocity = distance/time. Assuming it travelled 1m in 1s, velocity = 1m/s.
final velocity when ball reaches the end of ramp = initial velocity of ball at the start of horizontal plane
thus, final velocity = v(horizontal)/ cos(theta) -- same as eq 2
with the final velocity, we can use eqn 1 to calculate the acceleration assuming we have the length of ramp.
Is this method correct? or am i missing something? this method will only work if assuming there is no loss of mechanical energy??