Calculating Acceleration with Friction and Applied Force

[dance_sg]

Homework Statement

A sled and cargo weighing 490 N is towed by a tractor over a horizontal field where the coefficient of sliding friction is 0.400. If the tractor exerts a force of 300 N, what is the acceleration of the sled?

Homework Equations

Fk/µkM

The Attempt at a Solution

i Tried changing the 490N to Kg by dividing it by 9.81. that gave me 49.95. i then multiplied that by 0.400. then i divided that final number from 300 N.

 

[rl.bhat]

Homework Statement

A sled and cargo weighing 490 N is towed by a tractor over a horizontal field where the coefficient of sliding friction is 0.400. If the tractor exerts a force of 300 N, what is the acceleration of the sled?

Homework Equations

Fk/µkM

The Attempt at a Solution

i Tried changing the 490N to Kg by dividing it by 9.81. that gave me 49.95. i then multiplied that by 0.400. then i divided that final number from 300 N.

490 N is the normal reaction. So the frictional force f_k= μ_kN.
Acceleration = (F - f_k)/m

 

[dance_sg]

O thank you so much :)