Calculating Acceleration with Known Velocity and Distance - Homework Problem

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Homework Help Overview

The problem involves calculating the acceleration of an object given its final velocity, time, and distance covered. The context is kinematics, specifically relating to motion equations.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the initial velocity's role in the calculations, with some expressing uncertainty about whether it is zero. There are attempts to set up equations based on the given variables, and questions arise regarding the correct interpretation of the equations.

Discussion Status

Several participants have provided equations and attempted to solve for acceleration, with some suggesting the need for multiple equations to account for unknowns. There is acknowledgment of potential errors in calculated values, indicating an ongoing exploration of the problem.

Contextual Notes

There is a noted ambiguity regarding the initial velocity, which affects the calculations. Participants are working within the constraints of the problem as presented, with no explicit consensus on the initial conditions.

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Homework Statement



An object takes 1.20 seconds to reach a velocity of 12.6 m/s. What is its acceleration if it covered 11.34 meters?

Homework Equations



Vf ^2 = Vi ^ 2 + 2ad

The Attempt at a Solution



Well, I am not sure if the initial velocity is zero or if it is starting at some velocity x.

My attempt:

12.6^2 = 0^2 + 2(a)(11.34)

a = 7 m/s^2

I know this is wrong but I don't understand how to solve it if I don't know what the initial velocity is?

Thank you.
 
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I would be really glad if someone could quickly explain this to me because I am having a hard time with acceleration problems. Thank you.
 
Looks like you'll need to solve more than one equation. Write separate equations for the distance covered and the final velocity given that there is an initial velocity. Two equations, two unknowns. You only need to find one of them (a).
 
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12.6 ^2 = Vi ^2 + (2)(a)(11.34)

12.6 = Vi + a (1.2 seconds)

After substituting Vi from equation 2 into equation number 1, I find that the acceleration is 4.25m/s/s.

THANK YOU THANK YOU THANK YOU.
 
Speedking96 said:
12.6 ^2 = Vi ^2 + (2)(a)(11.34)

12.6 = Vi + a (1.2 seconds)

After substituting Vi from equation 2 into equation number 1, I find that the acceleration is 4.25m/s/s.

THANK YOU THANK YOU THANK YOU.

Maybe a typo, but check your acceleration value. 4.25?
 
gneill said:
Maybe a typo, but check your acceleration value. 4.25?

Woops. It's 5.25 m/s/s.
 
a=v/t with that you have the time then plug it into another equation.
 
Speedking96 said:
Woops. It's 5.25 m/s/s.

:approve:
 

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