Calculating Angular and Linear Speed and period of revolution

  • Thread starter FaraDazed
  • Start date
  • #1
347
2

Homework Statement


A toy truck moves around the outside of a circle of radius 0.6m at 2 revolutions per second

Calculate:
a: the angular speed of the truck
b: the linear speed of the truck
c: the period of revolution


Homework Equations


[itex]
ω= \frac{2π}{T} \\
v=rω
[/itex]
??

The Attempt at a Solution


For part a i have done..
[itex]
ω= \frac{2π}{T} \\
ω= \frac{2π}{0.5} \\
ω= 12.56 rads/s
[/itex]

I used 0.5 as it says it rotates twice per second so one rotation would take half a second (i think this maybe wrong).

For part b i have done..
[itex]
v=rω \\
v=0.6 \times 12.56 \\
v= 7.54m/s \\
[/itex]
Obviously this depends on whether I got part a correct.

For part c I am not sure what the question is asking for but at a guess I did what I did in part A..

2 revolutions per second, therefore 1 revolution would take 0.5s.

Any help is appreciated.
 
Last edited:

Answers and Replies

  • #2
1,198
5
What is 2 divided by .5? Last time I checked it was 4.
 
  • #3
347
2
What is 2 divided by .5? Last time I checked it was 4.

I understand that, but where does that relate to my answers? Have I divided 2 by 0.5 anywhere?

I do usually miss obvious things, and I cant see this one, could you point it out please?

EDIT: sorry I just released this mistake (i think) and rectified it.
 
  • #4
1,198
5
Last time I looked your first answer was 3.14 rad/sec for angular velocity. Now it has been changed to 12.56 radians/sec.
 
  • #5
380
7
I am not a native English speaker but I think it means the time one rotation takes. So for c T=0.5s
 
  • #6
347
2
Could anyone have another look please and see if there is anything wrong with it now? Any help is appreciated :)
 
  • #7
1,198
5
It is correct. Angular speed is 4*pi; linear speed is 2.4*pi; period is 0.5 seconds.
 

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