Calculating Angular and Linear Speed and period of revolution

1. Feb 3, 2013

FaraDazed

1. The problem statement, all variables and given/known data
A toy truck moves around the outside of a circle of radius 0.6m at 2 revolutions per second

Calculate:
a: the angular speed of the truck
b: the linear speed of the truck
c: the period of revolution

2. Relevant equations
$ω= \frac{2π}{T} \\ v=rω$
??

3. The attempt at a solution
For part a i have done..
$ω= \frac{2π}{T} \\ ω= \frac{2π}{0.5} \\ ω= 12.56 rads/s$

I used 0.5 as it says it rotates twice per second so one rotation would take half a second (i think this maybe wrong).

For part b i have done..
$v=rω \\ v=0.6 \times 12.56 \\ v= 7.54m/s \\$
Obviously this depends on whether I got part a correct.

For part c I am not sure what the question is asking for but at a guess I did what I did in part A..

2 revolutions per second, therefore 1 revolution would take 0.5s.

Any help is appreciated.

Last edited: Feb 3, 2013
2. Feb 3, 2013

LawrenceC

What is 2 divided by .5? Last time I checked it was 4.

3. Feb 3, 2013

FaraDazed

I understand that, but where does that relate to my answers? Have I divided 2 by 0.5 anywhere?

I do usually miss obvious things, and I cant see this one, could you point it out please?

EDIT: sorry I just released this mistake (i think) and rectified it.

4. Feb 3, 2013

LawrenceC

Last time I looked your first answer was 3.14 rad/sec for angular velocity. Now it has been changed to 12.56 radians/sec.

5. Feb 3, 2013

lep11

I am not a native English speaker but I think it means the time one rotation takes. So for c T=0.5s

6. Feb 4, 2013

FaraDazed

Could anyone have another look please and see if there is anything wrong with it now? Any help is appreciated :)

7. Feb 4, 2013

LawrenceC

It is correct. Angular speed is 4*pi; linear speed is 2.4*pi; period is 0.5 seconds.

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