Calculating angular displacement of clockhands

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SUMMARY

The angular displacement of the second hand of a clock in one hour is 360 degrees or 2π radians, as it completes one full rotation. The minute hand also completes one full rotation in one hour, resulting in the same angular displacement of 360 degrees or 2π radians. The hour hand, however, moves only 1/12 of a full rotation in one hour, corresponding to 30 degrees or π/6 radians. Understanding these calculations is essential for solving problems related to rotational motion.

PREREQUISITES
  • Understanding of angular displacement and radians
  • Basic knowledge of circular motion
  • Familiarity with the concept of rotational speed
  • Ability to convert between degrees and radians
NEXT STEPS
  • Study the relationship between angular velocity and angular displacement
  • Learn about the equations of motion for rotational dynamics
  • Explore the concept of periodic motion in physics
  • Investigate real-world applications of angular displacement in engineering
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Students studying physics, educators teaching mechanics, and anyone interested in understanding the principles of rotational motion and angular displacement.

DeeAussie
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Homework Statement


What is the a.d of each of the following hands of a clock in 1h?
the second and?
the minute hand?
the hour hand?


Homework Equations


That's what I'm looking for


The Attempt at a Solution


I'm having trouble getting it on paper, just a description of how one of you might crack this would be wonderful.


thank you
 
Physics news on Phys.org
Going around a circle exactly once corresponds to [tex]2 \pi[/tex] radians (of angular displacement). Going around the circle twice is twice that. Going half way around the circle is 1/2 that, and so on.

So what's the angular displacement (i.e. how many radians are traversed) of a hand that goes around exactly once? One that goes around 60 times? And 60 x 60 times?
 

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