bigsaucy
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Hello all, just a few problems that I've worked through, just clarifying if I'm on the right track. Thank you in advance.
1.) The radius of the Earth is 6378.1 km and completes one revolution per day. Calculate the difference in apparent weight between a person of 65kg mass, standing on the south pole and a person of the same mass standing on the equator. (Assume both are at sea-level).
My Solution:
The velocity at which the Earth rotates is simply 2pi(6378.1km) divided by the time taken in seconds (86400 seconds since it takes 24 hours to rotate) this gives 0.46 m/s. The centrifugal force felt by an individual at the equator is then the opposite of the centripetal force which gives -0.00214N. The individual at the south pole feels the full pull of the Earth at 9.8 m/s^2.
Therefore the difference in apparent weight is just 0.00214N.
1.) The radius of the Earth is 6378.1 km and completes one revolution per day. Calculate the difference in apparent weight between a person of 65kg mass, standing on the south pole and a person of the same mass standing on the equator. (Assume both are at sea-level).
My Solution:
The velocity at which the Earth rotates is simply 2pi(6378.1km) divided by the time taken in seconds (86400 seconds since it takes 24 hours to rotate) this gives 0.46 m/s. The centrifugal force felt by an individual at the equator is then the opposite of the centripetal force which gives -0.00214N. The individual at the south pole feels the full pull of the Earth at 9.8 m/s^2.
Therefore the difference in apparent weight is just 0.00214N.
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