Calculating Area of Polar Function: Spiral r = 5(e^.1θ)

[klarge]

1. Problem: Use the spiral r = 5(e^.1θ). Find the area of the region in Quadrant I that is outside the second revolution of the spiral and inside the third revolution.



2. Homework Equations :

3. Attempt at solution:

My problem with finding the area of a polar graph is determining the bounds, so to get the right bounds for this graph do I set the equation equal to zero? I am really at a loss as to how to set up the bounds. Any hints would be helpful.

 

[jhicks]

So... the second revolution is between which values of \theta and the third is between which values of \theta? \theta = 0 is the start of the first.

 

[klarge]

2nd between -2pi and 2pi and the third between -4pi and 4pi?

 

[jhicks]

One full revolution is 2\pi radians. If revolution 1 is for 0 < \theta < 2\pi and the second revolution starts at \theta = 2\pi radians and spans 2\pi subsequent radians, the second revolution has what range of \theta?.

 

[klarge]

2\pi < \theta < 4\pi
and the third would be 4\pi < \theta < 6\pi.

 

[jhicks]

Correct.

 

[klarge]

So the bounds would be between 2\pi < \theta < 4\pi?