tag16
- 95
- 0
x + y = 1
92.011 x + 46.0055 y = 77.4395
x= -y + 1
92.011 (-y +1) + 46.0055 y = 77.4395
-92.011 y + 92.011 + 46.0055 y = 77.4395
-46.0055 y + 92.011= 77.4395
-46.0055 y = -14.5715
y = 0.316734
1- y = x
x = 0.683266
To find the degree of dissociation I did this:
n(N2O4)=77.4395/92=0.841 mol
degree dissociation: x(N2O4)/n(N2O4)= 0.683266/0.841= 0.812445= 81.24%
To find Kp I did:
n(N2O4)=77.4395/92=0.841 mol
n(NO2)= 77.4395/46=1.683 mol
Kp= n(N2O4)/(n(NO2))^2= 0.841/(1.683)^2= 0.296912
I think to find delta G standard I'd want to use this equation: delta G= -RTlnKp
and for delta S: delta S= delta G/T
Did I go about any of that right or is that not what I'm suppose to do?
92.011 x + 46.0055 y = 77.4395
x= -y + 1
92.011 (-y +1) + 46.0055 y = 77.4395
-92.011 y + 92.011 + 46.0055 y = 77.4395
-46.0055 y + 92.011= 77.4395
-46.0055 y = -14.5715
y = 0.316734
1- y = x
x = 0.683266
To find the degree of dissociation I did this:
n(N2O4)=77.4395/92=0.841 mol
degree dissociation: x(N2O4)/n(N2O4)= 0.683266/0.841= 0.812445= 81.24%
To find Kp I did:
n(N2O4)=77.4395/92=0.841 mol
n(NO2)= 77.4395/46=1.683 mol
Kp= n(N2O4)/(n(NO2))^2= 0.841/(1.683)^2= 0.296912
I think to find delta G standard I'd want to use this equation: delta G= -RTlnKp
and for delta S: delta S= delta G/T
Did I go about any of that right or is that not what I'm suppose to do?