Calculating Average Velocity of Dropped Bolt From High-Rise Building

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SUMMARY

The discussion focuses on calculating the average velocity of a bolt dropped from a height of 320 meters using the function s(t) = 320 - 5t² over the interval from t = 3 to t = 8 seconds. The average velocity is computed using the formula Δs/Δt, resulting in an average velocity of 55 m/s. However, it is emphasized that the negative sign should be retained to indicate the downward direction of the velocity, leading to an average velocity of -55 m/s.

PREREQUISITES
  • Understanding of kinematic equations, specifically s(t) = s₀ + vt + ½at²
  • Knowledge of average velocity calculation using Δs/Δt
  • Familiarity with the concept of direction in velocity
  • Basic algebra skills for manipulating equations
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  • Study the implications of negative velocity in physics contexts
  • Explore the derivation of kinematic equations for free-fall scenarios
  • Learn about the effects of air resistance on falling objects
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Homework Statement



A construction worker drops a bolt while working on a high-rise building 320m above the ground. After t seconds, the bolt has fallen a distance of s metres, where s(t) = 320-5t^2, 0 <= t <=8

Find the average velocity for the interval 3<=y<=8

Homework Equations





The Attempt at a Solution



I used the formulas \Deltas / \Deltat
which then =
s(8) - s(3) / (8-3)

~
~
=55

Is this right?
 
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The magnitude is correct but I think you want to keep the negative sign to indicate direction.
 

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