Equations for average and maximum velocity

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SUMMARY

The discussion centers on calculating the maximum and average velocity of an object dropped from a height of 45 meters under the influence of gravity (9.81 m/s²). The user correctly identifies the equations for maximum velocity (V = v(final) - v(initial) = a x (delta)t) and average velocity (V(avg) = (sqrt(2 x g x (delta)y)) / 2). However, it is noted that the average velocity can be computed more efficiently using a simplified approach. The user seeks confirmation on their methodology rather than the final answers.

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  • Understanding of kinematic equations
  • Basic knowledge of gravitational acceleration
  • Familiarity with the concept of velocity
  • Ability to perform square root calculations
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  • Learn about the implications of gravitational acceleration on velocity
  • Explore alternative methods for calculating average velocity in free-fall scenarios
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Homework Statement


Given height dropped and gravity constant, what is the maximum and average velocity of an object dropped from a building.
Gravity- 9.81
(Delta)y- 45 m. Height from which object is dropped
T- 3.1 seconds

Homework Equations


V= v(final)-v(initial)= a x (delta)t
V(avg)= (sqrt (2 x g x (delta)y)) / 2

The Attempt at a Solution


I'm not looking for the answers, just reassurance I'm on the right track and using the right equations. So above I think I have the right equation for maximum velocity for the first equation and average velocity for the second equation.
 
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The formulas are right, but the average velocity can be calculated in a much easier way.
 

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