Calculating Baud Rate for Analog Signaling

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The discussion focuses on calculating the baud rate for an analog signaling system using 4 phase shifts and 8 amplitude levels at a bit rate of 100 Kbits/s. The initial calculation attempted to use a logarithmic approach but was deemed incorrect. The correct method identifies that there are 32 unique symbols from the combinations of phase shifts and amplitudes. Consequently, the baud rate is determined by dividing the bit rate by the number of symbols, resulting in a baud rate of 3,125 baud. This calculation highlights the relationship between bit rate, symbol combinations, and baud rate in analog signaling.
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We are using analog signaling to transmit our data. If we utilize 4 different phase shifts and 8 different amplitudes and the bit rate is 100 Kbits/s what is the baud rate of the channel?




I was thinking that it is


log_{2} (4 * 8)/100 =1/20




but i think it is wrong.
 
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I'm very rusty so might be totally wrong but...

The baud rate is generally the symbol rate. If I've understood correctly you have 32 different symbols/combinations (4 * 8 = 32). So I believe the baud rate is 100,000/32.
 

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