Calculating Change in Volume of a Shrinking Sphere

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SUMMARY

The discussion focuses on calculating the change in volume of a shrinking sphere using the formula V(sphere) = 4/3(pi)(r^3). Given that the initial volume is 36pi in³ and the radius decreases by dr = -0.2 in, the participant successfully derived the change in volume (dV) by substituting the radius and the change in radius into the derivative. The conclusion drawn is that the volume must decrease as the radius shrinks, eliminating any answers suggesting an increase in volume as geometrically nonsensical.

PREREQUISITES
  • Understanding of calculus, specifically differentiation
  • Familiarity with the formula for the volume of a sphere
  • Basic knowledge of geometric principles related to volume
  • Ability to interpret and manipulate mathematical equations
NEXT STEPS
  • Study the application of derivatives in real-world volume change problems
  • Learn about related rates in calculus
  • Explore geometric interpretations of volume changes in three-dimensional shapes
  • Investigate the implications of volume changes in physical contexts, such as fluid dynamics
USEFUL FOR

Students studying calculus, particularly those focusing on related rates and volume calculations, as well as educators looking for practical examples of geometric principles in action.

Qube
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Homework Statement



http://i.minus.com/jbxIzu0P7sTqP0.png

Homework Equations



V(sphere) = 4/3(pi)(r^3)

V = 36pi in^3

dr = -0.2 in

dV = ?

The Attempt at a Solution



I basically solved for the radius, and took the derivative and plugged in the value of the radius and the change in the radius to get the change in the volume.

http://i.minus.com/jbsA5BJkMOPHgl.jpg

Also upon further consideration it appears that one can easily eliminate the answers that claim the volume increases since that wouldn't make any geometric sense; if the radius was shrinking one would naturally expect the volume of a sphere to follow suit.
 
Last edited by a moderator:
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I see no question here.
 
Qube said:

Homework Statement



http://i.minus.com/jbxIzu0P7sTqP0.png

Homework Equations



V(sphere) = 4/3(pi)(r^3)

V = 36pi in^3

dr = -0.2 in

dV = ?

The Attempt at a Solution



I basically solved for the radius, and took the derivative and plugged in the value of the radius and the change in the radius to get the change in the volume.

http://i.minus.com/jbsA5BJkMOPHgl.jpg

Also upon further consideration it appears that one can easily eliminate the answers that claim the volume increases since that wouldn't make any geometric sense; if the radius was shrinking one would naturally expect the volume of a sphere to follow suit.

Looks good!
 
Last edited by a moderator:

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