Calculating Changing Velocity of a Rocket on Excel

Click For Summary
SUMMARY

The discussion focuses on calculating the changing velocity of a rocket using Excel, specifically addressing the limitations of basic integral equations. The constant thrust of 20,000 N and the rocket's mass of 2,000 kg, with 600 kg not made of fuel and a fuel loss of 20 kg per second, are critical parameters. The correct approach involves using the rocket equation, which is based on the conservation of momentum, rather than simple acceleration formulas. Participants emphasize the need for a proper derivation of the rocket equation for accurate modeling.

PREREQUISITES
  • Understanding of basic calculus, specifically integration
  • Familiarity with the rocket equation and its derivation
  • Knowledge of Newton's laws of motion
  • Proficiency in using Excel for mathematical modeling
NEXT STEPS
  • Research the derivation of the rocket equation
  • Learn how to implement numerical integration in Excel
  • Explore the effects of varying thrust on rocket velocity
  • Study the impact of gravitational forces on rocket motion
USEFUL FOR

Aerospace engineers, physics students, and anyone interested in modeling rocket dynamics and optimizing calculations in Excel.

Procrastinate
Messages
155
Reaction score
0
I am attempting to work out the changing velocity of a rocket on Excel. However, I cannot use the simple:

\int{a} dt = v.

at + C = v.


If thrust is constant at 20 000 and the rocket is 2000kg with 600kg not made of fuel and 20kg lost every second, then would the equation be:

\int{\frac{20000}{1400-20t}} dt = v.

This is forgetting about acceleration due to gravity for the moment.
 
Physics news on Phys.org
Your integral is not quite right (you should have delta-v on the right side, not v-dot) and your second equation (delta-v = at) is only correct when acceleration is constant.

For a proper way to model this you want to look at the rocket equation which is derived from the principle of conserved total momentum of the rocket and its ejected mass. You probably want to search for a derivation of this equation in your textbooks or on the net, but otherwise feel free to ask more questions.
 

Similar threads

  • · Replies 22 ·
Replies
22
Views
3K
Replies
5
Views
2K
  • · Replies 16 ·
Replies
16
Views
9K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 8 ·
Replies
8
Views
4K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 9 ·
Replies
9
Views
4K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 3 ·
Replies
3
Views
2K