Calculating Coefficient of Kinetic Friction for a Hockey Puck

Click For Summary

Homework Help Overview

The problem involves calculating the coefficient of kinetic friction for a hockey puck sliding on ice, given its initial speed and the distance it travels before stopping. The subject area includes kinematics and frictional forces.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss finding acceleration using the initial speed and distance, with one participant questioning the validity of their approach. There is a suggestion to assume uniform acceleration and to utilize relevant kinematic equations to find acceleration.

Discussion Status

The discussion is ongoing, with participants exploring different methods to calculate acceleration and questioning the assumptions made. Some guidance has been offered regarding the use of known quantities and relevant equations.

Contextual Notes

Participants note the lack of time as a variable and the challenge of calculating force without knowing the mass of the puck. There is an emphasis on using the initial and final speeds in the analysis.

Psyguy22
Messages
62
Reaction score
0
A hockey puck on a frozen pond with an initial speed of 12.3 m/s stops after sliding a distance of 198.9 m. Calculate the average value of the coefficient of kinetic friction between the puck and the ice.

So I started with finding the acceleration. I divided 12.3m/s by 198.9m then took the inverse (so units would go back seconds) and came up with 16.17s. So now I have Δv and Δt so I divided 12.3m/s by 16.17s to get an acceleration of .76m/s^2

I also know that friction equals μN and that F=ma. Since N=mg and friction is the only force acting on the object, i divided the mass out. So I had μg=a, or μ=a/g. (using 9.81m/s^2 as gravity) So μ=.0774 which seemed reasonable for ice. But I don't know how to find the actual force without knowing the mass. Am I even heading in the right direction?
 
Physics news on Phys.org
Psyguy22 said:
So I started with finding the acceleration. I divided 12.3m/s by 198.9m then took the inverse (so units would go back seconds) and came up with 16.17s. So now I have Δv and Δt so I divided 12.3m/s by 16.17s to get an acceleration of .76m/s^2
That does not work.
To travel 198.9m in 16.17s, it would have to travel at 12.3m/s the whole time, which is clearly not the case. You need a different approach here.

I also know that friction equals μN and that F=ma. Since N=mg and friction is the only force acting on the object, i divided the mass out. So I had μg=a, or μ=a/g. (using 9.81m/s^2 as gravity) So μ=.0774 which seemed reasonable for ice. But I don't know how to find the actual force without knowing the mass. Am I even heading in the right direction?
That part is good, once you fix your acceleration value. You cannot, and do not have to, calculate the force.
 
Then how do I find acceleration? I don't have time..
 
But you do know lots of other things. For example, you know the initial and the final speeds. I think it's okay to assume uniform acceleration here. You probably have a list of equations for dealing with this sort of motion that look something like, for example, v = u + at.

What you need to do is find an equation that includes the quantities that you know along with the acceleration. Then there's some algebra to find a.
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
3K
Replies
5
Views
3K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 16 ·
Replies
16
Views
6K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
1
Views
4K
  • · Replies 20 ·
Replies
20
Views
3K
Replies
3
Views
10K
  • · Replies 8 ·
Replies
8
Views
1K