Calculating Collision Speeds: Billiard Ball Physics Homework Solution

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SUMMARY

The discussion focuses on solving a physics problem involving the collision of two billiard balls. Ball 1, initially moving at 5.00 m/s, collides with stationary Ball 2, resulting in Ball 1 moving at 4.35 m/s post-collision. The conservation of momentum principle is applied using the equation m1v1 = m2v2 to determine the speed of Ball 2 after the collision. The correct application of momentum conservation leads to the conclusion that Ball 2 moves at a speed of 1.65 m/s after the impact.

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  • Understanding of momentum conservation principles
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  • Ability to solve algebraic equations
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Homework Statement



A billiard ball (ball 1) moving at 5.00 m/s strikes a stationary ball (ball 2) of the same mass. After the collision, Ball 1 moves at a speed of 4.35 m/s. Find the speed of ball 2 after collision


Homework Equations



Find speed



The Attempt at a Solution



The equation I am usuing m1v1=m2v2 seems like it might fit??
 
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After the collision, the balls are moving in the different directions. Resolve the momentums after collision. And solve for the velocity of m2.
 

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