Calculating Common Velocity of Two Identical Blocks After Collision

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SUMMARY

The discussion centers on calculating the common velocity of two identical blocks after a collision, where one block travels at 3v and the other at 2v. Using the conservation of momentum, the derived common velocity is v' = 2.5v. However, the expected answer provided in the discussion is 1.5v, indicating a discrepancy that requires further examination of the problem's parameters or assumptions.

PREREQUISITES
  • Understanding of conservation of momentum principles
  • Basic knowledge of collision mechanics
  • Familiarity with algebraic manipulation of equations
  • Concept of identical mass in physics problems
NEXT STEPS
  • Review the principles of conservation of momentum in elastic and inelastic collisions
  • Examine examples of collision problems involving identical masses
  • Learn about the implications of direction and velocity in collision scenarios
  • Investigate common pitfalls in solving physics problems related to momentum
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and collision theory, as well as educators seeking to clarify concepts related to momentum and velocity in collisions.

dalcde
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Homework Statement


Two identical blocks of the same mass travel at velocities of 3v and 2v on a smooth surface as shown (same direction).
Two blocks move together after collision. What is their common velocity?

Homework Equations


Conservation of momentum

The Attempt at a Solution


Let v' be the common velocity.

3mv+2mv = 2mv'
v'= 2.5v

Therefore the veloctiy is 2.5v. Answer given is 1.5v.
 
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From the information given the answer should be 2.5 v.
 
Thank you
 

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