Calculating constant of elasticity of springs in a car

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SUMMARY

The discussion centers on the calculation of the constant of elasticity (k) for springs in a car's suspension system. Participants clarify that when analyzing the system, the professor's use of k refers to the individual spring constant, not the total for all four springs. To find the effective spring constant for the entire system, one must either divide the total weight by four or multiply the individual spring constant by four, depending on the context of the calculation.

PREREQUISITES
  • Understanding of Hooke's Law and spring constants
  • Basic knowledge of mechanical engineering principles
  • Familiarity with car suspension systems
  • Ability to perform algebraic manipulations in physics equations
NEXT STEPS
  • Research the application of Hooke's Law in multi-spring systems
  • Explore the dynamics of car suspension systems
  • Learn about the calculation of effective spring constants in parallel and series configurations
  • Study the impact of spring constants on vehicle handling and ride comfort
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Mechanical engineers, automotive engineers, physics students, and anyone interested in the mechanics of car suspension systems.

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Homework Statement
There's a car of 500 kg, and a man of 60 kg enters the car. When this happens, the centre of mass of the car goes down ##0,3 cm##.
Determine the constant of elasticity of the springs
Relevant Equations
Newton's and Hooke's equations
When my professor solved it, he wrote ##k## in the equations. But there are four springs, so why didn't he write ##4k##?
 
Last edited:
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If he is talking about each spring individually he needs either to divide the weight by four or multiply the k by 4..
 

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