Calculating Cooling Load for Water Tank on Building Roof?

Click For Summary

Discussion Overview

The discussion revolves around calculating the cooling load for a water tank located on a building roof. The participant is specifically focused on cooling a 5 cubic meter water tank from 55 to 25 degrees Celsius, considering factors such as insulation and heat transfer calculations.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Homework-related

Main Points Raised

  • The participant outlines the cooling load calculation using the formula q = m * c * delta T, where they express concerns about the results being nonsensical.
  • The participant provides their calculation steps, which yield a cooling requirement of 10.75 TR, and questions whether this is excessively large for the intended application.
  • Another participant requests clarification on the initial calculations and suggests that incorporating additional factors may require different relations.

Areas of Agreement / Disagreement

There is no consensus on the correctness of the calculations or the appropriateness of the cooling load result. The discussion remains unresolved regarding the validity of the calculations and the selection of the cooling coil.

Contextual Notes

The calculations presented depend on the assumptions made regarding the mass of water and specific heat capacity. There may be missing considerations regarding heat gain from solar exposure and the efficiency of the cooling system.

gaber2611
Messages
14
Reaction score
0
Hello everybody,

I have been here before, with different username and cause i didn't log into long time ago, the username doesn't work for m now, so here i am with the new user.

Just as a respect for the forum rules, to not post a topic once i register.

i am doing cooling load calculations, for cooling a 5 cubic meters volume water tank, drains 1000l/day, exposed to sun, installed on building roof, to cool water from 55 to 25 celcuis degrees, working hours of the coil is 12hrs during the day.

i am thinking to insulate the tank, so solar heat gain won't be taken into account for cooling load, and it will be only the heat transfer between the water and fereon cooling coil, which can be calculated using the formula:

q= m*c*delta t

i calculated it, and the result didn't make sense to me, so i need your help with the calculation result.
will appreciate your reply, as i am in urgent need to do that work.
Thanks in advance.
 
Engineering news on Phys.org
What you're calculating is the heat transfer rate of the water to change the temperature from 55 to 25 degrees C. What doesn't it make sense? It'd be helpful if you gave us the calculation that you did. If you wanted to incorporate other factors it will require other relations.
 
Thanks vadar for your reply,

here is my calulations,which doesn't make sense to me:q= m * c * delta T
= (1*5)grams * 4.18 j/g.C * 30 C.
= 627 J (watt/sec.) , = 627*60 w/hr ,= 37.62 kw/hr.
1 TR = 3.5 kw, then q= 10.75 TR.

does this make sense to you?, when you buy a heat pump with that capacity?,isn't it too big?, or i did something wrong?,if wrong, what are the relations or procedures to select the right cooling coil for that water tank?
 
anyone to help?
 

Similar threads

Replies
5
Views
2K
Replies
7
Views
3K
Replies
2
Views
1K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 15 ·
Replies
15
Views
4K
  • · Replies 3 ·
Replies
3
Views
1K
Replies
36
Views
6K
Replies
9
Views
2K
Replies
17
Views
3K
Replies
1
Views
3K