Calculating Cosine Sum: Solving Complex Equations for Even Roots

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Homework Help Overview

The problem involves calculating a sum of cosine terms with arguments that are fractions of \(2\pi\) based on an integer \(n\). The context suggests a connection to complex equations and roots of unity.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the relationship between the cosine sum and the roots of the equation \(z^{2n+1} = 1\). There are suggestions to explore the properties of the complex plane and the spacing of arguments on the unit circle. Some participants express a need for clarity on previous attempts and what might be missing in their reasoning.

Discussion Status

The discussion is ongoing, with participants sharing ideas and questioning each other's approaches. Some guidance has been offered regarding the use of complex exponentials, but there is no clear consensus or resolution yet.

Contextual Notes

Participants are encouraged to provide more details about their attempts to facilitate better understanding and collaboration. There is an acknowledgment of the need to clarify assumptions and the mathematical framework being used.

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Homework Statement


Calculate
cos\frac{2\pi}{2n+1} + cos\frac{4\pi}{2n+1} + cos\frac{6\pi}{2n+1} + ... + cos\frac{2n\pi}{2n+1}


Homework Equations


Complex equations, maybe :p

The Attempt at a Solution


Let's say
z^{2n+1} = 1
The sum is equivalent to the sum of the real even roots of the equation above. That's it. Ideas?
 
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Dinheiro said:

Homework Statement


Calculate
cos\frac{2\pi}{2n+1} + cos\frac{4\pi}{2n+1} + cos\frac{6\pi}{2n+1} + ... + cos\frac{2n\pi}{2n+1}


Homework Equations


Complex equations, maybe :p

The Attempt at a Solution


Let's say
z^{2n+1} = 1
The sum is equivalent to the sum of the real even roots of the equation above. That's it. Ideas?

What are YOUR ideas?
 
Those were basically my ideas, I just didn't write down my complete attempt at the solution, sorry. But I could find out what was missing in my resolution xD Thanks, Ray
 
How are we supposed to see what's missing if you don't show us what you did?
 
You mention that, in the complex plane, the given arguments lie equally spaced about the unit circle so did you consider using cos(z)=(e^{iz}+ e^{-iz})/2?
 
Actually, I didn't solve it this way, but nice one though! Thanks, hallsoflvy
 

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