Calculating Current Density of Protons in Solar Wind at Earth | 691 km/s

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SUMMARY

The current density of protons in the solar wind near Earth, with a density of 10.0 cm-3 and a speed of 691 km/s, is calculated using the formula (nLA)e. After converting the proton density to 107 m-3 and using the charge of a proton (1.6E-19 C), the current density is determined to be 1.11E-7 A/m2. The total current received by Earth is calculated to be approximately 8.82E12 amperes by multiplying the current density by the surface area of a sphere with a radius of 6.371E6 m.

PREREQUISITES
  • Understanding of current density calculations
  • Knowledge of proton density and speed in solar wind
  • Familiarity with unit conversions (cm-3 to m-3)
  • Basic principles of electromagnetism and charge (e)
NEXT STEPS
  • Study the derivation of current density formulas in electromagnetism
  • Learn about solar wind characteristics and their impact on Earth
  • Explore the effects of varying proton densities on current calculations
  • Investigate the implications of solar wind currents on space weather
USEFUL FOR

Astrophysicists, space weather researchers, and students studying electromagnetism and solar phenomena will benefit from this discussion.

flash525
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Near earth, the density of protons in the solar wind is 10.0cm^-3, and their speed is 691 km/s.
a) find current density of these protons
b) what current in amperes does Earth receive




a. To find the current density I need to multiply (nLA)e
then after i get I divide it by A


The Attempt at a Solution



To find the current density I need to multiply (nLA)e

do i need to convert 10.0 protons cm^-3 to 10000000m^-3 because i tried that and it didnt work?
I guess my main question is do i have the conversions right:
v= 691000 m/s
n = 1 E7
e= 1.6E-19
the final answer i got was 1.11 E-7 (is this answer maybe negative?)
 
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b. To find the current in Amperes that Earth recieves I multiply the current density by the area:1.11E-7 * 4*π*(6.371E6)^2 = 8.82E12 amperes
 

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