Calculating density of an ideal gas

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SUMMARY

The discussion focuses on calculating the new density of helium gas when the temperature is raised from 0 degrees Celsius to 100 degrees Celsius while maintaining constant pressure. The ideal gas law, represented as PV = nRT, is utilized to derive the relationship between density, mass, and volume. Participants suggest using an arbitrary mass of helium to find the new volume at 373K, allowing for the calculation of density using the formula density = mass/volume. The key takeaway is that the density decreases with increasing temperature under constant pressure conditions.

PREREQUISITES
  • Understanding of the Ideal Gas Law (PV = nRT)
  • Basic knowledge of gas properties and behavior
  • Familiarity with unit analysis in physics and chemistry
  • Ability to perform calculations involving temperature conversions (Celsius to Kelvin)
NEXT STEPS
  • Learn about the relationship between temperature and density in gases
  • Study the concept of molar volume and its application in gas calculations
  • Explore the implications of the Ideal Gas Law in real-world scenarios
  • Investigate the effects of pressure changes on gas density
USEFUL FOR

Students studying chemistry or physics, particularly those focusing on gas laws and thermodynamics, as well as educators seeking to clarify concepts related to ideal gases and density calculations.

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Homework Statement


The density of helium gas at T= 0 degrees Celsius is 0.179 kg/m^3. The temperature is then raised to 100 degrees Celsius, but pressure is kept constant Assuming the helium gas is an ideal gas, calculate the new density of the gas.




Homework Equations


PV = nRT


The Attempt at a Solution


I thought that using PV = nRT --> Pm/density = nRT would be sufficient in solving this problem, but when I tried to solve this I found that I needed the mass of the molecule and there was no number of moles expressed for me to solve n, etc. So now I am stuck and not even sure if that is the proper equation to use. This problem seems simple enough, but I have myself all mixed up about it!
 
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Assume 1 L initial volume.

It is not necessary - if you will do calculations using symbols only, volume will cancel out. But assuming 1L you can calculate mass of the gas, then new volume, then new density.
 
Without moles, you can still calculate the ratio of the volume at T=100 C to the volume at T=0 C. Since you how much the volume changes you can find how much the density changes.

Alternately, you can choose an arbitrary amount of grams helium, convert it to moles n, and then plug it into PV=nRT with T=373K to find the volume occupied by that amount of helium. Divide whatever mass you initially chose by whatever volume you get to determine the density at T=100C.
 
Wouldn't setting it up this way also cancel out pressure along with volume? That would just give me the equation density = mass/volume and then if volume cancels I'm left with density = mass?
 
cavalier said:
Without moles, you can still calculate the ratio of the volume at T=100 C to the volume at T=0 C. Since you how much the volume changes you can find how much the density changes.

Alternately, you can choose an arbitrary amount of grams helium, convert it to moles n, and then plug it into PV=nRT with T=373K to find the volume occupied by that amount of helium. Divide whatever mass you initially chose by whatever volume you get to determine the density at T=100C.
so should I set it up as P1V1/T1 = P2V2/T2?
 
Yes, but there is only one P throughout the problem since P is constant. You can get rid of it.
 
cavalier said:
Yes, but there is only one P throughout the problem since P is constant. You can get rid of it.

okay, so now I have the mass, but how do I calculate the volume to use when solving for the final density?
when I set this up as density = mass/volume I end up with density being equal to the mass and I KNOW that is not correct!
 
Density=(mass/volume)(initial volume/final volume)

Unit analysis makes sense.
 

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