Calculating Density of States in One-Dimensional Metals at 0K

Join the discussion
Registration is free. Start your own thread to ask a follow-up.
1 reply · 3K views
kasse
Messages
383
Reaction score
1

Homework Statement



We study a one dimensional metal with length L at 0 K, and ignore the electron spin. Assume that the electrons do not interact with each other. The electron states are given by

[tex]\psi(x) = \frac{1}{\sqrt{L}}exp(ikx), \psi(x) = \psi(x + L)[/tex]

What is the density of states at the Fermi level for this metal?

The Attempt at a Solution



The total energy of the system is [tex]E = \frac{\hbar^{2}\pi^{2}n^{2}}{2mL^{2}}[/tex] where n is the square of the sums of the three quantum numbers that determine each quantum state.

At a certain energy all states up to [tex]E_{F}(0)=E_{0}n^{2}_{F}[/tex] is filled.
 
Last edited:
Physics news on Phys.org