Calculating Dipole Moment: 1.5uC at (0,3), (0,5)

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SUMMARY

The dipole moment for the charge distribution of 1.5 µC at coordinates (0,3) cm and (0,5) cm is calculated using the formula p = qd. With a distance (d) of 2 cm (0.02 m) and charge (q) of 1.5 µC (1.5E-6 C), the dipole moment (p) is determined to be 3E-8 Cm. The calculation is straightforward, confirming that the distributions behave like point charges, and no additional complexities are present in this scenario.

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Homework Statement



Determine the dipole moment for the following charge distributions: 1.5uC each at (0,3), (0,5), where the coordinates are in cm.

Homework Equations



p=qd

The Attempt at a Solution



Since the coordinates are (0,3) and (0,5) d is 2cm or 0.02m and q is 1.5uC or 1.5E-6C. Which then leads to p=(1.5E-6C)(0.02m)=3E-8Cm.

My only problem is that this seems way to easy. Am I missing something obvious?
 
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It seems to me like the distributions are like point charges and then it is simple.
 

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