Dipole moment, electric potential

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Homework Help Overview

The discussion revolves around calculating the total dipole moment of a system consisting of two charges, q1 and q2, and finding an equation for the electric potential due to this dipole moment. The charges are given specific values and distances, and the participants are exploring the implications of these values in the context of dipole moments and electric potential.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss separating the dipole moments for each charge and adding them together. There are questions about the direction of the dipole moment vector and the appropriate use of the potential formula. Some participants express uncertainty about the angle θ and how to represent the potential in vector form.

Discussion Status

The discussion is ongoing, with participants providing guidance on using vector notation and the dot product in relation to the dipole moment and potential. There is acknowledgment of the need for clarity regarding the formula for potential and the role of position in defining it.

Contextual Notes

Participants note a lack of clear definitions and teaching on the subject, which contributes to confusion regarding the application of formulas and the interpretation of variables involved in the calculations.

Cocoleia
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Homework Statement


I am given this picture
upload_2017-1-29_15-56-52.png

and I know that |q1|=2nC, |q2|=5nC, d=1mm
I need to first find the total dipole moment of the system. Then I need to find an equation that represents the electric potential due to this net dipole moment for all (everywhere)

Homework Equations


p=qd

The Attempt at a Solution


I saw a formula which was p=qd (vectors)
so I thought I would separate it into two different dipole moments, one for q1 and one for q2, and then add them together. For p1 I got 2x10^-12 in the y direction, and for p2 I got 5x10^-12 in the x direction. Would this be correct?

Also, would I be using this formula for the potential?
V = kpcosθ/r^2
 
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Cocoleia said:
I got 5x10^-12 in the x direction
What happened to the 3/2?
 
haruspex said:
What happened to the 3/2?
What is the direction of a dipole moment vector?
Ok, so 7.5x10^-12 in the x direction. And for the potential?
 
Cocoleia said:
And for the potential?
Assuming a certain definition of θ, yes.
 
haruspex said:
Assuming a certain definition of θ, yes.
I'm not quite sure what θ would be in this case
 
Cocoleia said:
I'm not quite sure what θ would be in this case
Maybe better to put the answer in vector form. If ##\vec p## is the dipole at the origin and ##\vec r## is a point in space, what is the potential at ##\vec r##?
 
haruspex said:
Maybe better to put the answer in vector form. If ##\vec p## is the dipole at the origin and ##\vec r## is a point in space, what is the potential at ##\vec r##?
I don't know what the formula for potential would be,except I had V=kpcosθ/r^2 in my notes but I don't know when to use it
 
Cocoleia said:
I don't know what the formula for potential would be,except I had V=kpcosθ/r^2 in my notes but I don't know when to use it
That makes for not terribly useful notes!
It arises from the dot product of the two vectors.
 
haruspex said:
That makes for not terribly useful notes!
It arises from the dot product of the two vectors.
So the dot product of p and r?
 
  • #10
Cocoleia said:
So the dot product of p and r?
Yes. Can you write the whole expression?
 
  • #11
haruspex said:
Yes. Can you write the whole expression?
I'm not really sure what you want, I assume r will have an x and y component, so r cosθ and r sinθ
so then
(7.5x10^-12)(rcosθ)+(2x10^-12)(rsinθ)

Sorry I don't really have any idea what I am doing because I have no notes/ teaching on this stuff.
 
  • #12
  • #15
haruspex said:
Yes.
What will the r hat be ?
 
  • #16
Cocoleia said:
What will the r hat be ?
Putting a hat on a vector is a standard notation meaning the unit vector in that direction. So for any vector ##\vec x##, ##\hat x=\frac{\vec x}{|\vec x|}##
 
  • #17
haruspex said:
Putting a hat on a vector is a standard notation meaning the unit vector in that direction. So for any vector ##\vec x##, ##\hat x=\frac{\vec x}{|\vec x|}##
Here they don't specify a length or direction for r, it just says "everywhere"
 
  • #18
Cocoleia said:
Here they don't specify a length or direction for r, it just says "everywhere"
The potential is necessarily a function of position. You cannot say what it is "everywhere" without involving a variable to specify position.
 

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