nwells1998
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What is the difference between average acceleration and average velocity?
The discussion revolves around understanding the concepts of average velocity and average acceleration in the context of circular motion, specifically involving an athlete running on a circular track. Participants explore the differences between these quantities and their implications in a scenario where speed remains constant.
Some participants have provided guidance on correcting misconceptions about the calculations involved, particularly regarding the circumference of the track and the method for determining displacement. There is an ongoing exploration of the correct approach to calculating average velocity and acceleration between specified points on the track.
Participants are working under the constraints of a homework assignment, which may impose specific requirements for calculations and interpretations of motion in circular paths. There is an emphasis on vector components and the need for accurate geometric understanding of the problem setup.
No, the units are different. You might have an object with an average velocity of 1 m/s and an average acceleration of 1 m/s², but those are not the same despite both having the number 1. Just like 1 orange is not the same as 1 apple.nwells1998 said:So can an object have the same average velocity and average acceleration?
Both velocity and acceleration are vector quantities. In other words they have a magnitude and a direction. If you change the direction of your velocity you have accelerated even if you have not changed the magnitude of your velocity (speed).nwells1998 said:An athlete starts at point A and runs at a constant speed of 6.0m/s around a round track 100m in diameter. find the x and y components of this runners average velocity and acceleration between points a, b, c, d (equally apart on circle).
So there is no acceleration because the speed is constant?
Careful: You found the area instead of the circumference.nwells1998 said:So...tell can you please tell me if I am on the right track?
A = (-50, 0) B = (0,50) C = (50, 0) D = (0, -50)
Circumference = (pi * r^2) = 7854m
Correct this. Also: The points are spaced 1/4 circumference apart.time between points = 7854m / 6.0m/s = 1309 s
nwells1998 said:oops...okay so the circumference is 314m.
Time between points is 314m / 6.0m/s / 4 13.0s between each section.
so for A - b
displacement Ax = (0-50m)/13s = -3.84 m/s
displacement Ay, A = (50-0)/13s = 3.84 m/s
VA = sq rt[(-3.84^2)+(3.84^2)] = 5.43 m/s
Aax = 3.84m/s^2 Aay = -3.84m/s^2