Calculating Displacement and Average Velocity/Acceleration for Circular Motion

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Homework Help Overview

The discussion revolves around understanding the concepts of average velocity and average acceleration in the context of circular motion, specifically involving an athlete running on a circular track. Participants explore the differences between these quantities and their implications in a scenario where speed remains constant.

Discussion Character

  • Conceptual clarification, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the definitions of average velocity and average acceleration, questioning whether an object can have the same values for both. They also explore the implications of constant speed on acceleration and the vector nature of these quantities.

Discussion Status

Some participants have provided guidance on correcting misconceptions about the calculations involved, particularly regarding the circumference of the track and the method for determining displacement. There is an ongoing exploration of the correct approach to calculating average velocity and acceleration between specified points on the track.

Contextual Notes

Participants are working under the constraints of a homework assignment, which may impose specific requirements for calculations and interpretations of motion in circular paths. There is an emphasis on vector components and the need for accurate geometric understanding of the problem setup.

nwells1998
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What is the difference between average acceleration and average velocity?
 
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Velocity and acceleration are two different quantities. Velocity is the rate of change of displacement; acceleration is the rate of change of velocity.
 
So can an object have the same average velocity and average acceleration?
 
nwells1998 said:
So can an object have the same average velocity and average acceleration?
No, the units are different. You might have an object with an average velocity of 1 m/s and an average acceleration of 1 m/s², but those are not the same despite both having the number 1. Just like 1 orange is not the same as 1 apple.
 
An athlete starts at point A and runs at a constant speed of 6.0m/s around a round track 100m in diameter. find the x and y components of this runners average velocity and acceleration between points a, b, c, d (equally apart on circle).

So there is no acceleration because the speed is constant?
 
nwells1998 said:
An athlete starts at point A and runs at a constant speed of 6.0m/s around a round track 100m in diameter. find the x and y components of this runners average velocity and acceleration between points a, b, c, d (equally apart on circle).

So there is no acceleration because the speed is constant?
Both velocity and acceleration are vector quantities. In other words they have a magnitude and a direction. If you change the direction of your velocity you have accelerated even if you have not changed the magnitude of your velocity (speed).
 
ah...okay I see...thanks, i will start working on this problem!
 
So...tell can you please tell me if I am on the right track?

A = (-50, 0) B = (0,50) C = (50, 0) D = (0, -50)

Circumference = (pi * r^2) = 7854m

time between points = 7854m / 6.0m/s = 1309 s

X components:
Vax, A = (0-50m)/1309s = -0.038 m/s

Aax, A = (0-50m/s)/1309s = -.038m/s/s
 
nwells1998 said:
So...tell can you please tell me if I am on the right track?

A = (-50, 0) B = (0,50) C = (50, 0) D = (0, -50)

Circumference = (pi * r^2) = 7854m
Careful: You found the area instead of the circumference.

time between points = 7854m / 6.0m/s = 1309 s
Correct this. Also: The points are spaced 1/4 circumference apart.

To find the average velocity between points A and B, for example, first find the displacement between A and B. (It's a vector that points from A to B.)
 
  • #10
oops...okay so the circumference is 314m.

Time between points is 314m / 6.0m/s / 4 13.0s between each section.

so for A - b

displacement Ax = (0-50m)/13s = -3.84 m/s
displacement Ay, A = (50-0)/13s = 3.84 m/s

VA = sq rt[(-3.84^2)+(3.84^2)] = 5.43 m/s

Aax = 3.84m/s^2 Aay = -3.84m/s^2
 
  • #11
Hi nwells1998,

nwells1998 said:
oops...okay so the circumference is 314m.

Time between points is 314m / 6.0m/s / 4 13.0s between each section.

so for A - b

displacement Ax = (0-50m)/13s = -3.84 m/s
displacement Ay, A = (50-0)/13s = 3.84 m/s

I don't believe this is right for the displacement, even though some of your numbers are right. Let's say point A is 50m to the west of the circle and point B is 50 m to the north of the circle. To find the displacement, you need to know how far B is from A, and also what direction B is from A. What would those answers be?

Then the average velocity is found from:

average velocity = displacement / time

VA = sq rt[(-3.84^2)+(3.84^2)] = 5.43 m/s

Aax = 3.84m/s^2 Aay = -3.84m/s^2

The average acceleration is (change in velocity)/(change in time). To answer that, you need to know what the velocities are at A and B. What are those?
 

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