Calculating Displacement with Friction and Air Resistance

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SUMMARY

The discussion focuses on calculating the distance a car travels before stopping due to drag force and friction. The car, with a mass of 1700 kg and an initial velocity of 54.22 m/s, experiences a drag force of 250 N and a friction coefficient of 0.1. Initial calculations show that without drag, the car travels 27.66 m, derived from kinetic energy and friction work. Participants emphasize the need to combine drag and friction forces to accurately determine the stopping distance.

PREREQUISITES
  • Understanding of Kinetic Energy calculations
  • Familiarity with Newton's laws of motion
  • Knowledge of friction and drag force concepts
  • Ability to perform work-energy calculations
NEXT STEPS
  • Learn how to calculate net forces acting on an object
  • Study the work-energy principle in physics
  • Explore drag force equations in fluid dynamics
  • Investigate combined effects of multiple forces on motion
USEFUL FOR

Students in physics, automotive engineers, and anyone interested in dynamics involving friction and drag forces.

ImAlwaysConfu
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Homework Statement



A car is rolling down a hill, it has a velocity of 54.22m/sec at the bottom of the hill. When it reaches the bottom of the hill, a fan begins to blow on it causing a drag force of 250N. Also, the tires create a friction coefficient of .1. The car eventually stops due to the Drag Force/Friction. Calculate how far the car will travel before stopping.



I can't figure out how to take into account the drag force. I know that before taking drag force into account, the car can travel 27.66m. I'm not sure if that helps or not. All I need to know is what formula to use and where I implement the drag force! Also, my homework is due TOMORROW AT 3PM EST. Any help before then will be awesome.
 
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How did you come to the 27.66 m? show your calcs without the drag force and I'll help with implementing the drag force...
 
First, I calculated for the Kinetic Energy which would be 1/2mv^2. 1/2(1700kg)(54.22m/sec) = 46,087J. Next, I calculated the impact friction would have: f=u(coeficcient of friction)F .1(1700)(9.8) = 1,666N. Then I calculted the work that would be done: Work = F(displacement) 46087J = 1,666N(displacement) then I divided 46087 by 1666 and came with 27.66M. If this is incorrect, could you tell me how to do it please? Thanks!
 
I think if I tell you that you would realize how easy it is. So you have an object working to the right with kinetic energy = 0.5*mv^2 your answer here is incorrect, do the calculation again... Now what is the total forces working against the vehicle? friction and drag, draw a FBD for your vehicle... Your methodology is good and accurate just combine everything now... The total force on the car is not just friction?
 

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