- #1

PhysWalk

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## Homework Statement

The question is as follows: An object falls from the top of the roof of a building. The object falls past a 3.5 meter high window somewhere on the building ,in 0.47 seconds. Find the distance between the top of the window and the roof.

## Homework Equations

V=d/t (Velocity = Distance over Time)

Vf^2=Vi^2 + 2ad (Velocity Final squared = Velocity initial squared + 2 times acceleration times distance)

I believe these are the equations that I should be using.

## The Attempt at a Solution

3.5/0.47 = 7.44681 = V

So, Vf = 7.44681, Vi = 0 (assuming the object falls from rest), Acceleration = 9.8m/s/s, distance = X

7.44681^2 = 0^2 + 2 (9.8) (d)

55.455=19.6 (d)

55.455/19.6 = 2.82934

d = 2.82934

d = 2.8 meters.

And that is what I have so far, 2.8 meters from the top of the window, to the roof. Would this be the right approach to the problem? Or have I made a mistake?