1. The problem statement, all variables and given/known data A falling stone takes 0.33 s to travel past a window 2.2 m tall. From what height above the top of the window did the stone fall? Express your answer using two significant figures. 2. Relevant equations Kinematic Equations ~ X= Vi (time) + .5gt^2 Vf^2 = Vi^2 + 2gx 3. The attempt at a solution First I determined what the initial velocity was at the top of the window: X = Vi (time) + .5gt^2 2.2 = Vi (.33) + .5 (-9.8) (.33)^2 Vi = 8.28 m/s Then I used this velocity as my final velocity in this equation: Vf^2 = Vi^2 + 2gx 8.28^2 = 0^2 + 2 (-9.8)x x = -3.5meters When I first inputted 3.5 meters into my online homework, it came out to be incorrect. I randomly decided to add -3.5 meters to 2.2 meters and the answer: 1.3 Meters, came out to be correct. I don't understand why I am adding -3.5 to 2.2. Thank you in advance.